pKa = 9.8N3-
pKa = -log(1.9x10^-5) = 4.72C5H5NH+
N3- is a weak base. The Kb is 1x10^-14 / 1.9x10^-5 . Which equals 5.3x10^-10 and the pKb = 9.28
The pKa of C5H5NH+ = 5.23
Thanks for your responses!
pKa = 9.8
ReplyDeleteN3-
pKa = -log(1.9x10^-5) = 4.72
ReplyDeleteC5H5NH+
N3- is a weak base. The Kb is 1x10^-14 / 1.9x10^-5 . Which equals 5.3x10^-10 and the pKb = 9.28
DeleteThe pKa of C5H5NH+ = 5.23
ReplyDeleteThanks for your responses!
ReplyDelete